2025 年 2 月USACO竞赛铜奖组问题一— Reflection

Farmer John has a square canvas represented by an N by N grid of cells (2≤N≤2000, N is even). He paints the canvas according to the following steps:

1.First, he divides the canvas into four equal quadrants, separated by horizontal and vertical lines through the center of the canvas.
2.Next, he paints a lovely painting in the top-right quadrant of the canvas. Each cell of the top-right quadrant will either be painted (represented by '#') or unpainted (represented by '.').
3.Finally, since he is so proud of his painting, he reflects it across the previously mentioned horizontal and vertical lines into the other quadrants of the canvas.

For example, suppose N=8 and FJ painted the following painting in the top-right quadrant in step 2:

.#..
.#..
.##.
....

Then after reflecting across the horizontal and vertical lines into the other quadrants in step 3, the canvas would look as follows:

..#..#..
..#..#..
.##..##.
........
........
.##..##.
..#..#..
..#..#..

However, while FJ was sleeping, Bessie broke into his barn and stole his precious canvas. She totally vandalized the canvas—removing some painted cells and adding more painted cells! Before FJ woke up, she returned the canvas to FJ.

FJ would like to modify his canvas so that it once again satisfies the reflective condition: that is, it is the result of reflecting the top-right quadrant into each of the other quadrants. Since he only has a limited number of resources, he would like to achieve this in as few operations as possible, where a single operation consists of either painting a cell or removing paint from a cell.

You are given the canvas after Bessie's vandalism, as well as a sequence of U
(0≤U≤105) updates to the canvas, each toggling a single cell to '.' if it is '#', or vice versa. Before any updates, and after each update, output the minimum number of operations x FJ needs to perform so that the reflective condition is satisfied.

INPUT FORMAT (input arrives from the terminal / stdin):

The first line contains integers N and U.

The next N lines each contain N characters representing the canvas after Bessie's vandalism. Every character is either '#' or '.'.

The following U lines each contain integers r and c, where 1≤r,cN, representing an update to the cell in the rth row from the top and cth column from the left of the canvas.

OUTPUT FORMAT (print output to the terminal / stdout):

Output U+1 lines representing x before any updates and after each update.

SAMPLE INPUT:

4 5
..#.
##.#
####
..##
1 3
2 3
4 3
4 4
4 4

SAMPLE OUTPUT:

4
3
2
1
0
1

The following canvas satisfies the reflective condition and differs from the original canvas by 4 operations:

....
####
####
....

It is impossible to make the original canvas satisfy the reflective condition using fewer than 4 operations.

After updating (1,3), the canvas looks like this:

....
##.#
####
..##
It now takes 3 operations to make the canvas satisfy the reflective condition.

After updating (2,3), the canvas looks like this:

....
####
####
..##

It now takes 2 operations to make the canvas satisfy the reflective condition.

SCORING:

Inputs 2-3: N≤4
Inputs 4-6: U≤10
Inputs 7-16: No additional constraints.

Problem credits: Chongtian Ma

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2025 年 2 月USACO竞赛银奖组问题三—Transforming Pairs

Bessie the brilliant bovine has discovered a new fascination—mathematical magic! One day, while trotting through the fields of Farmer John’s ranch, she stumbles upon two enchanted piles of hay. The first pile contains a bales, and the second pile contains b bales (1≤a,b≤1018).

Next to the hay, half-buried in the dirt, she discovers an ancient scroll. As she unfurls it, glowing letters reveal a prophecy:

To fulfill the decree of the Great Grasslands, the chosen one must transform these two humble hay piles into exactly c and d bales—no more, no less.

Bessie realizes she can only perform the following two spells:

She can magically conjure new bales to increase the first pile’s size by the amount currently in the second pile.
She can magically conjure new bales to increase the second pile’s size by the amount currently in the first pile.

She must perform these operations sequentially, but she can perform them any number of times and in any order. She must reach exactly c bales in the first pile and d bales in the second pile (1≤c,d≤1018).

For each of T(1≤T≤104) independent test cases, output the minimum number of operations needed to fulfill the prophecy, or if it is impossible to do so, output -1.

INPUT FORMAT (input arrives from the terminal / stdin):

The first line contains T.

The next T lines each contain four integers a,b,c,d.

OUTPUT FORMAT (print output to the terminal / stdout):

Output T lines, the answer to each test case.

SAMPLE INPUT:

4
5 3 5 2
5 3 8 19
5 3 19 8
5 3 5 3

SAMPLE OUTPUT:

-1
3
-1
0

In the first test case, it is impossible since b>d initially, but operations can only increase b.

In the second test case, initially the two piles have (5,3) bales. Bessie can first increase the first pile by the amount in the second pile, resulting in (8,3) bales. Bessie can then increase the second pile by the new amount in the first pile, and do this operation twice, resulting in (8,11) and finally (8,19) bales. This matches c and d and is the minimum number of operations to get there.

Note that the third test case has a different answer than the second because c and d are swapped (the order of the piles matters).

In the fourth test case, no operations are necessary.

SAMPLE INPUT:

1
1 1 1 1000000000000000000

SAMPLE OUTPUT:

999999999999999999

SCORING:

Inputs 3-4: max(c,d)≤20⋅min(a,b)
Inputs 5-7: T≤10 and a,b,c,d≤106
Inputs 8-12: No additional constraints

Problem credits: Benjamin Qi

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2025 年 2 月USACO竞赛银奖组问题二—Vocabulary Quiz

Bessie is helping Elsie with her upcoming vocabulary quiz. The words to be tested will be drawn from a bank of M distinct words, where no word in the bank is a prefix of another word in the bank.

While the bank is nonempty, Bessie will select a word from the bank, remove it from the bank, and read it to Elsie one character at a time from left to right. Elsie's task is to tell Bessie once she can uniquely identify it, after which Bessie will stop reading.

Bessie has already decided to read the words from the word bank in the order w1,w2,…,wM. If Elsie answers as quickly as possible, how many characters of each word will Bessie read?

The words are given in a compressed format. We will first define N+1 (1≤N≤ 106 ) distinct words, and then the word bank will consist of all those words that are not a prefix of another word. The words are defined as follows:

Initially, the 0th word will be the empty string.

Then for each 1≤i≤N, the ith word will be equal to the pith word plus an additional character at the end (0≤pi<i). The characters are chosen such that all N+1 words are distinct.

INPUT FORMAT (input arrives from the terminal / stdin):

The first line contains N, where N+1 is the number of words given in the  compressed format.

The next line contains p1,p2,…,pN where pi represents that the i-th word is formed by taking the pi-th word and adding a single character to the end.

Let M be the number of words that are not a prefix of some other word. The next M lines will contain w1,w2,…,wM, meaning that the with word will be the ith to be read. It is guaranteed that the words to be read form a permutation of the words in the word bank.

OUTPUT FORMAT (print output to the terminal / stdout):

Output M lines, where the ith line contains the number of characters of the ith word that Bessie reads.

SAMPLE INPUT:

5
0 1 2 3 4
5

SAMPLE OUTPUT:

0

There are 6words labeled 0…5. Word 5 is the only one that is not a prefix of another word, so it is the only one in the bank. In general, once only one word is left in the bank, Elsie won't need any characters to identify it.

SAMPLE INPUT:

4
0 0 1 1
4
3
2

SAMPLE OUTPUT:

2
1
0

The bank consists of words 2, 3, and 4.

Elsie needs two characters to identify word 4 since words 3 and 4 share their first character in common.

Once Bessie reads the first character of word 3 , Elsie has enough characters to uniquely identify it, since word 4 was already read.

SAMPLE INPUT:

4
0 0 1 1
2
3
4

SAMPLE OUTPUT:

1
2
0

SCORING:

Inputs 4-5: No word has length greater than 20.
Inputs 6-10: The sum of the lengths of all words in the word bank does not exceed 107.
Inputs 11-18: No additional constraints.

Problem credits: Benjamin Qi

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2025 年 2 月USACO竞赛银奖组问题一—The Best Lineup

Farmer John has N (1≤N≤2⋅105) cows in a line a. The i'th cow from the front of line a is labeled an integer ai (1≤ai N). Multiple cows may be labeled the same integer.

FJ will construct another line b in the following manner:

Initially, b is empty.
While a is nonempty, remove the cow at the front of a and potentially add that cow to the back of b.

FJ wants to construct line b such that the sequence of labels in b from front to back is lexicographically greatest (see the footnote).

Before FJ constructs line b, he can perform the following operation at most once:

Choose a cow in line a and move it anywhere before its current position.

Given that FJ optimally performs the aforementioned operation at most once, output the lexicographically greatest label sequence of b he can achieve.

Each input will consist of T (1≤T≤100) independent test cases.

INPUT FORMAT (input arrives from the terminal / stdin):

The first line contains T.

The first line of each test case contains N.

The second line of each test case contains N space-separated integers a1,a2,…,aN.

It is guaranteed that the sum of N over all test cases does not exceed 106.

OUTPUT FORMAT (print output to the terminal / stdout):

For each test case, output the lexicographically greatest b on a new line.

SAMPLE INPUT:

3
5
4 3 2 1 3
6
5 1 2 6 3 4
6
4 1 3 2 1 1

SAMPLE OUTPUT:

4 3 3 2 1
6 5 4
4 3 2 1 1

In the first test case, FJ can move the fifth cow to directly after the second cow. Now, a=[4,3,3,2,1]. It can be shown [4,3,3,2,1] is also the lexicographically greatest b.

In the second test case, FJ can move the fourth cow to the front of the line.

In the third test case, FJ does not need to perform any operations. He can construct b by adding each cow beside the second cow to the back of b. It can be shown this results in the lexicographically greatest b.

SCORING:

Inputs 2-4: N≤100
Inputs 5-8: N≤750
Inputs 9-18: No additional constraints

FOOTNOTE:

Recall that a sequence s is lexicographically greater than a sequence t if and only if one of the following holds:

At the first position i where siti, si>si.
If no such i exists, s is longer than t.

Problem credits: Chongtian Ma, Haokai Ma, Andrew Li

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2025 年 2 月USACO竞赛金奖组问题三—Friendship Editing

Farmer John's N cows are labeled 1 to N(2≤N≤16). The friendship relationships between the cows can be modeled as an undirected graph with M (0≤MN(N−1)/2) edges. Two cows are friends if and only if there is an edge between them in the graph.

In one operation, you can add or remove a single edge from the graph. Count the minimum number of operations required to ensure that the following property holds: If cows a and b are friends, then for every other cow c, at least one of a
and b is friends with c.

INPUT FORMAT (input arrives from the terminal / stdin):

The first line contains N and M.

The next M lines each contain a pair of friends a and b (1≤a<bN). No pair of friends appears more than once.

OUTPUT FORMAT (print output to the terminal / stdout):

The number of edges you need to add or remove.

SAMPLE INPUT:

3 1
1 2

SAMPLE OUTPUT:

1

The network violates the property. We can add one of edges (2,3)
or (1,3), or remove edge (1,2)to fix this.

SAMPLE INPUT:

3 2
1 2
2 3

SAMPLE OUTPUT:

0
No changes are necessary.

SAMPLE INPUT:

4 4
1 2
1 3
1 4
2 3

SAMPLE OUTPUT:

1

SCORING:

Inputs 4-13: One input for each N∈[6,15] in increasing order.
Inputs 14-18: N=16

Problem credits: Benjamin Qi

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2025 年 2 月USACO竞赛金奖组问题二—The Best Subsequence

Farmer John has a binary string of length N (1≤N≤109), initially all zeros.

He will first perform M(1≤M≤2⋅105) updates on the string, in order. Each update flips every character from l to r. Specifically, flipping a character changes it from 0 to 1, or vice versa.

Then, he asks you Q (1≤Q≤2⋅105) queries. For each query, he asks you to output the lexicographically greatest subsequence of length k comprised of characters from the substring from l to r. If your answer is a binary string s1s2…sk, then output (that is, its value when interpreted as a binary number) modulo 109+7.

A subsequence is a string that can be derived from another string by deleting some or no characters without changing the order of the remaining characters.

Recall that string A is lexicographically greater than string B of equal length if and only if at the first position i, if it exists, where AiBi, we have Ai>Bi.

INPUT FORMAT (input arrives from the terminal / stdin):

The first line contains N, M, and Q.

The next M lines contain two integers, l and r (1≤lrN) — the endpoints of each update.

The next Q lines contain three integers, l, r, and k (1≤lrN,1≤krl+1) — the endpoints of each query and the length of the subsequence.

OUTPUT FORMAT (print output to the terminal / stdout):

Output Q lines. The ith line should contain the answer for the ith query.

SAMPLE INPUT:

5 3 9
1 5
2 4
3 3
1 5 5
1 5 4
1 5 3
1 5 2
1 5 1
2 5 4
2 5 3
2 5 2
2 5 1

SAMPLE OUTPUT:

21
13
7
3
1
5
5
3
1

After performing the M operations, the string is 10101.

For the first query, there is only one subsequence of length 5, 10101, which is interpreted as 1⋅24+0⋅23+1⋅22+0⋅21+1⋅20=21.

For the second query, there are 5 unique subsequences of length 4: 0101, 1101, 1001, 1011, 1010. The lexicographically largest subsequence is 1101, which is interpreted as 1⋅23+1⋅22+0⋅21+1⋅20=13.

For the third query, the lexicographically largest sequence is 111, which is interpreted as 7.

SAMPLE INPUT:

9 1 1
7 9
1 8 8

SAMPLE OUTPUT:

3

SAMPLE INPUT:

30 1 1
1 30
1 30 30

SAMPLE OUTPUT:

73741816

Make sure to output the answer modulo 109 +7.

SCORING:

Input 4: N≤10,Q≤1000
Input 5: M≤10
Inputs 6-7: N,Q≤1000
Inputs 8-12: N≤2⋅105 
Inputs 13-20: No additional constraints.

Problem credits: Chongtian Ma

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2025 年 2 月USACO竞赛金奖组问题一—Bessie's Function

Bessie has a special function f(x) that takes as input an integer in [1,N]
and returns an integer in [1,N] (1≤N≤2⋅105). Her function f(x) is defined by N
integers a1aN where f(x)=ax (1≤aiN).

Bessie wants this function to be idempotent. In other words, it should satisfy f(f(x))=f(x)for all integers x∈[1,N].

For a cost of ci, Bessie can change the value of ai to any integer in [1,N] (1≤ci≤109). Determine the minimum total cost Bessie needs to make f(x)
idempotent.

INPUT FORMAT (input arrives from the terminal / stdin):

The first line contains N.

The second line contains N

space-separated integers a1,a2,…,aN.

The third line contains N space-separated integers c1,c2,…,cN.

OUTPUT FORMAT (print output to the terminal / stdout):

Output the minimum total cost Bessie needs to make f(x) idempotent.

SAMPLE INPUT:

5
2 4 4 5 3
1 1 1 1 1

SAMPLE OUTPUT:

3

We can change a1=4, a4=4, a5=4. Since all ci equal one, the total cost is equal to 3
, the number of changes. It can be shown that there is no solution with only 2
or fewer changes.

SAMPLE INPUT:

8
1 2 5 5 3 3 4 4
9 9 2 5 9 9 9 9

SAMPLE OUTPUT:

7

We change a3=3 and a4=4. The total cost is 2+5=7.

SCORING:

Subtasks:

Input 3: N≤20
Inputs 4-9:aii
Inputs 10-15: All aiare distinct.
Inputs 16-21: No additional constraints.
Additionally, in each of the last three subtasks, the first half of tests will satisfy ci=1 for all i.

Problem credits: Avnith Vijayram

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2025 年 2 月USACO竞赛白金组问题三—True or False Test

Bessie is taking an N-question true or false test (1≤N≤2⋅105). For the i-th question, she will gain apoints if she gets it correct, lose bi points if she gets it incorrect, or remain even if she does not answer it (0<ai,bi ≤109).

Bessie knows all the answers because she is a smart cow, but worries that Elsie (who is administering the test) will retroactively change up to k of the questions after the test such that Bessie does not get those questions correct.

Given Q (1≤QN+1) candidate values of k (0≤kN), determine the number of points Bessie can guarantee for each k, given that she must answer at least k questions.

INPUT FORMAT (input arrives from the terminal / stdin):

The first line contains N and Q.

The next N lines each contain ai and bi.

The next Q lines each contain a value of k. No value of k appears more than once.

OUTPUT FORMAT (print output to the terminal / stdout):

The answer for each k on a separate line.

SAMPLE INPUT:

2 3
3 1
4 2
2
1
0

SAMPLE OUTPUT:

-3
1
7

For each value of k, it is optimal for Bessie to answer all of the questions.

SCORING:

Inputs 2-4: N≤100
Inputs 5-7: Q≤10, N≤2⋅105 
Inputs 7-20: No additional constraints.

Problem credits: Benjamin Qi

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2025 年 2 月USACO竞赛白金组问题二—Transforming Pairs

Answer Q(1≤Q≤105) independent queries each of the following form:

You are given four integers a,b,c,d(−1018≤a,b,c,d≤1018). In one operation you can either do a+=b, or b+=a. Determine the minimum number of operations to transform (a,b) into (c,d), or if it is impossible to do so, output −1.

INPUT FORMAT (input arrives from the terminal / stdin):

The first line contains Q.

The next Q lines each contain four integers a,b,c,d.

OUTPUT FORMAT (print output to the terminal / stdout):

The answer for each query on a separate line.

SAMPLE INPUT:

4
5 -3 -1 -3
5 3 5 2
5 3 8 19
5 3 5 3

SAMPLE OUTPUT:

2
-1
3
0

First query: (5,−3)→(2,−3)→(−1,−3)

Second query: Impossible.

Third query: (5,3)→(8,3)→(8,11)→(8,19)

Fourth query: No operations necessary.

SCORING:

Input 2: |a|,|b|,|c|,|d|≤10
Input 3: a,b≥0
Input 4: a≥0≥b
Input 5: a≤0≤b
Input 6: a,b≤0
Input 7: c,d≥0
Input 8: c≥0≥d
Input 9: c≤0≤d
Input 10: c,d≤0
Inputs 11-14: Q≤103
Inputs 15-19: No additional constraints.

Problem credits: Benjamin Qi

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2025 年 2 月USACO竞赛白金组问题一—Min Max Subarrays

注意:此问题的时限为 3 秒,是默认值的 1.5 倍。

You are given a length-N integer array a1,a2,…,aN (2≤N≤106,1≤aiN
). Output the sum of the answers for the subproblem below over all N(N+1)/2
contiguous subarrays of a.

Given a nonempty list of integers, alternate the following operations (starting with the first operation) until the list has size exactly one.

1.Replace two consecutive integers in the list with their minimum.
2.Replace two consecutive integers in the list with their maximum.

Determine the maximum possible value of the final remaining integer.

For example,

[4, 10, 3] -> [4, 3] -> [4]
[3, 4, 10] -> [3, 10] -> [10]

In the first array, (10,3) is replaced by min(10,3)=3 and (4,3) is replaced by max(4,3)=4.

INPUT FORMAT (input arrives from the terminal / stdin):

The first line contains N.

The second line contains a1,a2,…,aN.

OUTPUT FORMAT (print output to the terminal / stdout):

The sum of the answer to the subproblem over all subarrays.

SAMPLE INPUT:

2
2 1

SAMPLE OUTPUT:

4

The answer for [2] is 2, the answer for [1] is 1, and the answer for [2,1] is 1.

Thus, our output should be 2+1+1=4.

SAMPLE INPUT:

3
3 1 3

SAMPLE OUTPUT:

12

SAMPLE INPUT:

4
2 4 1 3

SAMPLE OUTPUT:

22

Consider the subarray [2,4,1,3].

1.Applying the first operation on (1, 3), our new array is [2,4,1].
2.Applying the second operation on (4, 1), our new array is [2,4].
3.Applying the third operation on (2, 4), our final number is 2.

It can be proven that 2 is the maximum possible value of the final number.

SCORING:

Inputs 4-5: N≤100
Inputs 6-7: N≤5000
Inputs 8-9: max(a)≤10
Inputs 10-13: No additional constraints.

Problem credits: Benjamin Qi

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